{"id":5259,"date":"2024-06-29T00:14:18","date_gmt":"2024-06-29T00:14:18","guid":{"rendered":"https:\/\/vartmaaninstitutesirsa.com\/?page_id=5259"},"modified":"2024-06-29T00:19:32","modified_gmt":"2024-06-29T00:19:32","slug":"biot-savarts-law","status":"publish","type":"page","link":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/biot-savarts-law\/","title":{"rendered":"Biot Savart\u2019s Law"},"content":{"rendered":"

6 Biot Savart\u2019s Law:-<\/span><\/u><\/strong>\u00a0m.imp<\/sup><\/span><\/u><\/strong>\u00a0<\/span><\/u><\/strong><\/h1>\n

As we know when current passes through a conductor, then magnetic field set up around the conductor which was firstly calculated by Jean Biot & Felix Savart called Biot Savart\u2019s Law.<\/span><\/p>\n

\"F:\\unitAccording to this law, the magnitude of magnetic field d<\/span>\"\"\u00a0at a point due to current following through a conductor is depends upon, current , length of conductor, distance of point from conductor & angle between point and conductor as<\/span><\/p>\n

\u00a0\u00a0<\/span>\"\"<\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

Combining all eq<\/span>n<\/sup><\/span>s we get<\/span>\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

\u00a0<\/span>\"\"<\/p>\n

Or<\/span>\u00a0\u00a0\u00a0\u00a0<\/span>\"\"\u00a0\u00a0\u00a0\u00a0<\/span>=<\/span>\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

Where<\/span>\u00a0\u00a0<\/span>K<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>=\u00a0<\/span>\"\"\u00a0= 10<\/span>-7<\/sup><\/span>\u00a0\u00a0<\/sup><\/span>TmA<\/span>-1<\/sup><\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/sup><\/span><\/p>\n

\u00a0<\/sup><\/span>Here u<\/span>0<\/sub><\/span>\u00a0called\u00a0<\/span>permeability of free space<\/span><\/u><\/em>.\u00a0<\/span><\/p>\n

\"\"So Biot Savart\u2019s law become\u00a0<\/span><\/p>\n

\u00a0<\/span>\"\"\u00a0\u00a0\u00a0<\/span>=<\/span>\u00a0\u00a0<\/span>\"\"<\/p>\n

In vector form<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

\u00a0\u00a0\u00a0<\/span>\"\"\u00a0\u00a0<\/span><\/strong>=<\/span><\/strong>\u00a0\u00a0\u00a0<\/span><\/strong>\"\"<\/p>\n

The direction of dB can be given by right hand rule.\u00a0<\/span><\/p>\n

Imp.<\/sup><\/span><\/em><\/strong>\u00a0<\/sup><\/span><\/strong>In present case the direction of\u00a0<\/span><\/em>\"\"\u00a0is perpendicular to plane of paper containing both\u00a0<\/span><\/em>\"\"\u00a0&\u00a0<\/span><\/em>\"\"\u00a0in inward direction; if P point lies in L.H.S then in outwards direction.<\/span><\/em><\/p>\n

Special cases:-<\/span><\/u><\/strong><\/p>\n

    \n
  1. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\u00a0 If\u00a0\u00a0\u00a0 \"\"<\/li>\n<\/ol>\n

    \"\"<\/p>\n

      \n
    1. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\u00a0\u00a0<\/span>If\u00a0<\/span>\"\"<\/li>\n<\/ol>\n

      \"\"<\/p>\n

      \u00a0\u00a0<\/span>I,e.\u00a0<\/span>magnetic field at a point perpendicular to current element is maximum<\/span><\/em><\/p>\n

      \uf0fc<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>This law is applicable for infinite small conductor.<\/span><\/p>\n

      \uf0fc<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>This law is similar to coulomb\u2019s law in electrostatics.<\/span><\/p>\n

      \uf0fc<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>This law is difficult to verify experimentally because it is difficult to construct infinite small conductor.<\/span><\/p>\n

       <\/p>\n

      7 Biot Savart\u2019s law V\/s Coulomb\u2019s Law:-<\/span><\/u><\/strong><\/p>\n

      As according to Coulomb\u2019s Law<\/span>\u00a0\u00a0<\/span><\/p>\n

      \u00a0\u00a0<\/span>\"\"=<\/span>\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

      & from Biot Savart\u2019s law<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

      dB =<\/span>\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

      On comparing above eq<\/span>n<\/sup><\/span>s we can give similarity & dissimilarity between both.<\/span><\/p>\n

      Similarity<\/span><\/u><\/p>\n

        \n
      1. Both the law obey inverse square law (\u03b1 \"\")<\/li>\n
      2. Both the law obeys principle of Superposition.<\/li>\n<\/ol>\n

        Dissimilarity:-<\/span><\/u><\/p>\n

          \n
        1. The source of magnetic field is current while source of electric field is charged.<\/li>\n
        2. Electric field exists due to both rest & motion of charge while magnetic field exists due to motion of charge.<\/li>\n
        3. The magnetic field is angle dependent while electric field is not.<\/li>\n
        4. <\/li>\n<\/ol>\n

          8 Magnetic field due to a long straight Conductor carrying current:-<\/span><\/u><\/strong>\u00a0m.imp<\/sup><\/span><\/u><\/strong><\/p>\n

          Suppose a point P having a distance a from the straight conductor carrying current I, then according to Biot savart Law, the magnetic field\u00a0<\/span>\"\"\u00a0\u00a0<\/span>at P due to small current element\u00a0<\/span>\"\",<\/span>\u00a0\u00a0\u00a0<\/span>r distance apart is<\/span><\/p>\n

          \"F:\\unit\u00a0<\/span>\"\"\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>–(1)<\/span><\/p>\n

          Now from \u0394 COP<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

          \"\"\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

          Or<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\"\"\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>(i)<\/span><\/p>\n

          Also<\/span>\u00a0\u00a0<\/span>\"\"<\/p>\n

          \"\"\u00a0\u00a0\u00a0\u00a0<\/span>(ii)<\/span><\/p>\n

          As<\/span>\u00a0\u00a0\u00a0\u00a0<\/span>tan<\/span>\"\"\u00a0\u00a0<\/span>=\u00a0<\/span>\"\"<\/p>\n

          \u21d2\u00a0\u00a0\u00a0<\/span>\"\"\u00a0= a tan<\/span>\"\"<\/p>\n

          Differentiating both side d<\/span>\"\"\u00a0=a sec<\/span>2<\/sup><\/span>\u00a0<\/span>\"\".d<\/span>\"\"\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>(iii)<\/span><\/p>\n

          Using all values in eq<\/span>n<\/sup><\/span>s (1) we get<\/span>\u00a0\u00a0\u00a0<\/span><\/p>\n

          \u00a0<\/span>\"\"=<\/span>\"\"<\/p>\n

          Or<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\"\"\u00a0=\u00a0<\/span>\"\"<\/p>\n

          To calculate complete magnetic field integrating both sides we get<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

          B =\u00a0<\/span>\"\"\u00a0<\/span>\"\"<\/p>\n

          B =\u00a0<\/span>\"\"\u00a0<\/span>\"\"<\/p>\n

          B =<\/span>\"\"\u00a0<\/span>\"\"\u00a0[Sin<\/span>\"\"2\u00a0<\/sub><\/span>\u2013 Sin(-<\/span>\u2205<\/span>1<\/sub><\/span>)]<\/span><\/p>\n

          Or<\/span>\u00a0\u00a0\u00a0<\/span>B =<\/span><\/strong>\"\"\u00a0<\/span><\/strong>\"\"\u00a0\u00a0\u00a0\u00a0<\/span><\/strong>[Sin<\/span><\/strong>\u2205<\/span><\/strong>1\u00a0<\/sub><\/span><\/strong>+ Sin<\/span><\/strong>\u2205<\/span><\/strong>2<\/sub><\/span><\/strong>]<\/span><\/strong>\u00a0\u00a0\u00a0<\/span><\/p>\n

          The direction of B can be given by\u00a0<\/span>Right hand rule<\/span><\/em>.<\/span><\/p>\n

          Special cases:-<\/span><\/u><\/p>\n

            \n
          1. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>If the conductor is infinite long & point P lies near to the dipole then<\/li>\n<\/ol>\n

            B =<\/span>\"\"\u00a0<\/span>\"\"\u00a0[sin90<\/span>0<\/sup><\/span>\u00a0<\/sub><\/span>+ sin90<\/span>0<\/sup><\/span>]<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

            Or<\/span>\u00a0<\/span>B =<\/span><\/strong>\"\"\u00a0<\/span><\/strong>\"\"=\u00a0<\/span><\/strong>\"\"\u00a0\u00a0<\/span><\/p>\n

              \n
            1. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span> If the conductor is infinite long but P lies near end y then\u00a0 \u2205<\/span>1<\/sub><\/span>=\u00a0 90,\u00a0 \u2205<\/span>2\u00a0<\/sub><\/span>=0<\/li>\n<\/ol>\n

              B =\u00a0<\/span>\"\"\u00a0[sin90<\/span>\u00a0<\/sub><\/span>+ sin0]<\/span>\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              \u00a0<\/span>=<\/span>\"\"\u00a0<\/span>\"\"\u00a0<\/span><\/p>\n

              \"\"Q1. A current of 10A is flowing from east to west in a long straight wire kept on a horizontal table. The magnetic field developed at a distance 10cm vertically above the wire is:\u00a0<\/span><\/strong><\/p>\n

              Ans:\u00a0<\/span>\"\"\u00a0\u00a0<\/span><\/p>\n

              \u00a0<\/span>So\u00a0<\/span>\"\"<\/p>\n

              Q2. A straight wire of mass 200 g and length 1.5 m carries a current of 2 A. It is suspended in mid-air by a uniform horizontal magnetic field B (Fig. 4.3). What is the magnitude of the magnetic field?<\/span><\/strong><\/p>\n

              Solution we find that there is an upward force F, of magnitude<\/span>\"\", for mid-air suspension, this must be balanced by the force due to gravity:<\/span>\u00a0\u00a0\u00a0<\/span>\"\"\u00a0\u00a0\u00a0<\/span><\/p>\n

              \u21d2<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

              \"\"0.65 T<\/span><\/p>\n

              Note that it would have been sufficient to specify<\/span>\"\", the mass per unit length of the wire. The earth\u2019s magnetic field is approximately 4 \u00d7 10<\/span>\u20135<\/sup><\/span>T and we have ignored it.<\/span><\/p>\n

              \"\"\u00a0Q3.<\/span><\/strong>\u00a0\u00a0<\/span><\/strong>An element<\/span><\/strong>\u00a0\u00a0<\/span><\/strong>\"\"\u00a0\u00a0<\/span><\/strong>is placed at the origin and carries a large current I = 10 A. What is the magnetic field on the y-axis at a distance of 0.5 m. \u2206x = 1 cm.\u00a0<\/span><\/strong><\/p>\n

              Solution<\/span>\"\"\u00a0\u00a0<\/span>here\u00a0<\/span>\"\"\u00a0<\/span><\/p>\n

              \"\"<\/p>\n

              \"\"\u00a0,<\/span><\/p>\n

              \u00a0<\/span>\"\"<\/p>\n

              \u21d2<\/span>\u00a0\u00a0<\/span>\"\"<\/p>\n

              \"\"\u00a0\u00a0<\/span>\"\"<\/p>\n

              The direction of the field is in the +z-direction.\u00a0<\/span><\/p>\n

              As<\/span>\u00a0\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

              \"\"<\/p>\n

               <\/p>\n

              9 Magnetic field At the Center Of The Circular Coil Carrying current:-<\/span><\/u><\/strong>\u00a0m.imp<\/sup><\/span><\/u><\/strong><\/p>\n

              \"F:\\unitAccording to Biot Savart Law, the magnetic field at the center of circular coil carrying current can be given as<\/span>\u00a0\u00a0\u00a0<\/span><\/p>\n

              \u00a0<\/span>\"\"\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>–(1)<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              \u00a0<\/span>(Here\u00a0<\/span>\"\"\u00a0is angle between current element Id<\/span>\"\"\u00a0& r. )<\/span><\/p>\n

              As radius is always perpendicular to tangent\u00a0<\/span><\/p>\n

              so<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\u03b8= 90<\/span>0<\/sup><\/span>\u00a0<\/span>\u21d2<\/span>\u00a0 \u00a0<\/span>sin90= 1<\/span><\/p>\n

              So<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

              To calculate complete magnetic field, integrate both sides\u00a0<\/span><\/p>\n

              \u21d2\u00a0\u00a0\u00a0\u00a0 B =<\/span>\"\"\u0283<\/span>\"\"\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              Here \u0283<\/span>\"\"\u00a0circumference of circle<\/span>\u00a0\u00a0<\/span><\/p>\n

              \u21d2<\/span> \u00a0\u00a0 B =<\/span>\"\"r<\/span><\/p>\n

              Or<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>B =<\/span>\"\"<\/p>\n

              If the circular coil contains n turns then<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              B =\u00a0<\/span>\"\"\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              or<\/span><\/strong>\u00a0\u00a0\u00a0\u00a0<\/span><\/strong>B=\u00a0<\/span><\/strong>\"\"<\/p>\n

              Here the direction of magnetic field can be given by right hand rule.<\/span>\u00a0<\/span><\/p>\n

              Q4. The magnetic dipole moment of a current carrying coil does not depend upon:<\/span><\/strong><\/p>\n

              A Number of turns of the coil<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              B Cross-sectional area of the coil<\/span><\/p>\n

              C Current flowing in the coil<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              D Material of the turns of the coil<\/span><\/strong><\/p>\n

              Q5. An electron is revolving around the nucleus in a circular orbit with a speed of\u00a0<\/span><\/strong>\"\"\u00a0m\/s . If the radius of the orbit is\u00a0<\/span><\/strong>\"\"\u00a0m, find the current constituted by the revolving electron in the orbit<\/span><\/strong><\/p>\n

              Solution\u00a0<\/span>\"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              Q6. A steady current of 2A flows through a circular coil having 5 turns of radius 7cm. The coil lies in X-Y plane with its centre at the origin. Find the magnitude and direction of the magnetic dipole moment of the coil.<\/span><\/strong><\/p>\n

              Ans:\u00a0<\/span>\"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              Q7.<\/span><\/strong>\u00a0\u00a0<\/span><\/strong>Consider a tightly wound 100 turns coil of radius 10 cm, carrying a current of 1 A. What is the magnitude of the magnetic field at the centre of the coil?<\/span><\/strong><\/p>\n

              Solution Since radius r = 10 cm = 0.1 m. The number of turns n = 100.\u00a0<\/span><\/p>\n

              So B=\u00a0<\/span>\"\"<\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              10 Magnetic field at a point on the axis of a circular coil carrying current:-<\/span><\/u><\/strong><\/p>\n

              Suppose a point P on the axis of a Circular coil carrying current I. Suppose two small current element\u00a0<\/span>\"\"\u00a0&\u00a0<\/span>\"\"\u00a0on coil. Then the Magnetic field due to these current Elements at P is dB & dB\u2019. As shown in fig.\u00a0<\/span><\/p>\n

              Clearly dB & dB\u2019 are equal. Resolving dB & dB\u2019 into rectangular components, we see that\u00a0<\/span>\"\"\u00a0&\u00a0<\/span>\"\"\u00a0\u00a0<\/span>are equal & opposite so they are cancelled out.\u00a0<\/span><\/p>\n

              So the total magnetic induction at P due to current through the whole circular coil is given<\/span>\u00a0\u00a0<\/span><\/p>\n

              B =\u0283dB Sin<\/span>\u2205<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>\u2013(i)<\/span><\/p>\n

              From Ampere circuital law, the magnetic induction due to\u00a0<\/span>\"\"\u00a0at P is<\/span>\u00a0\u00a0<\/span><\/p>\n

              \"\"<\/p>\n

              \"\"<\/p>\n

              \"F:\\unit<\/p>\n

               <\/p>\n

               <\/p>\n

               <\/p>\n

               <\/p>\n

               <\/p>\n

               <\/p>\n

               <\/p>\n

               <\/p>\n

              Here\u00a0<\/span>\"\"\u00a0is angle between r &\u00a0<\/span>\"\"\u00a0so 90<\/span>0<\/sup><\/span>.<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              So<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>dB =<\/span>\"\"<\/p>\n

              Using in (i)\u00a0<\/span><\/p>\n

              B =<\/span>\u00a0\u00a0\u00a0<\/span>\u0283<\/span>\"\"\u00a0<\/span>\"\"<\/p>\n

              Here<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>sin<\/span>\u2205<\/span>\u00a0\u00a0<\/span>\"\"\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>&<\/span>\u00a0\u00a0\u00a0<\/span>\u0283 d<\/span>\"\"\u00a0=2<\/span>\"\"<\/p>\n

              \u00a0\u00a0\u00a0\u00a0<\/span>\u21d2 \u00a0\u00a0\u00a0<\/span>B =<\/span>\"\".<\/span>\"\"\u00a02<\/span>\"\"<\/p>\n

              Or<\/span>\u00a0\u00a0\u00a0<\/span>\"\"<\/p>\n

              If there are n turn in the coil\u00a0<\/span><\/p>\n

              then<\/span>\u00a0\u00a0\u00a0<\/span>B =\u00a0<\/span>\"\"<\/p>\n

              \uf0fc<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>at center\u00a0<\/span>\"\"\u00a0=0<\/span>\u00a0\u00a0\u00a0<\/span>\u21d2<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/span><\/p>\n

              B =\u00a0<\/span>\"\"<\/p>\n

              \"\"<\/p>\n

              \uf0fc<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>If P point lies far away from the coil then\u00a0<\/span>\"\"\u00a0a so a can be neglected\u00a0<\/span><\/p>\n

              \u21d2<\/span> \u00a0\u00a0 B =<\/span>\"\"<\/p>\n

              =<\/span>\"\"<\/p>\n

              \uf0fc<\/span>\u00a0\u00a0\u00a0\u00a0\u00a0<\/span>If P point lies at a distance equal to radius of the coil I,e. r = a we have<\/span><\/p>\n

              \u21d2\u00a0\u00a0 B=\u00a0<\/span>\"\"\u00a0<\/span><\/p>\n

              =<\/span>\"\"\u00a0<\/span><\/p>\n

              \"\"<\/p>\n

              11 The direction of magnet field due to circular coil:-<\/span><\/u><\/strong>\u00a0m.imp<\/sup><\/span><\/u><\/strong>\u00a0<\/strong><\/p>\n

              As we can see the magnetic lines form Close loop at the end of the circular coil & straight line at the center of the loop. The direction of these magnetic lines can be given by Right hand rule.<\/span><\/p>\n

              \"F:\\unit<\/p>\n

              \u00a0<\/span><\/p>\n

              \u00a0<\/span><\/p>\n

              \u00a0<\/span><\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

               <\/p>\n

              12 Right hand rule:-<\/span><\/u><\/strong>\u00a0<\/span><\/strong><\/p>\n

              \"\"Suppose the current is flowing through a circular conductor, if we imagine the fingers of the right hand curling in the direction of current, then the thumb will point in the direction of magnetic field.<\/span><\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

              13 Clock rule:-<\/span><\/u><\/strong>\u00a0<\/strong><\/p>\n

              According to clock rule if current moves in anti clock wise direction, the upper face of loop or coil is behave as north pole & when current moves in clock wise direction, then upper face behave as south pole.<\/span><\/p>\n

              \"F:\\unit<\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

              \u00a0<\/span><\/strong><\/p>\n

               <\/p>\n

              Chapter 4 Moving Charges and Magnetism<\/a><\/h3>\n

              class 12 physics notes\u00a0<\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

              6 Biot Savart\u2019s Law:-\u00a0m.imp\u00a0 As we know when current passes through a conductor, then magnetic field set up around the conductor which was firstly calculated by Jean Biot & Felix Savart called Biot Savart\u2019s Law. According to this law, the magnitude of magnetic field d\u00a0at a point due to current following through a conductor is […]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_uag_custom_page_level_css":"","site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-4)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"class_list":["post-5259","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_hostinger_reach_plugin_has_subscription_block":false,"_hostinger_reach_plugin_is_elementor":false,"uagb_featured_image_src":{"full":false,"thumbnail":false,"medium":false,"medium_large":false,"large":false,"1536x1536":false,"2048x2048":false},"uagb_author_info":{"display_name":"sandeep.soni484@gmail.com","author_link":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/author\/sandeep-soni484gmail-com\/"},"uagb_comment_info":0,"uagb_excerpt":"6 Biot Savart\u2019s Law:-\u00a0m.imp\u00a0 As we know when current passes through a conductor, then magnetic field set up around the conductor which was firstly calculated by Jean Biot & Felix Savart called Biot Savart\u2019s Law. According to this law, the magnitude of magnetic field d\u00a0at a point due to current following through a conductor is…","_links":{"self":[{"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/pages\/5259","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/comments?post=5259"}],"version-history":[{"count":3,"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/pages\/5259\/revisions"}],"predecessor-version":[{"id":5265,"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/pages\/5259\/revisions\/5265"}],"wp:attachment":[{"href":"https:\/\/vartmaaninstitutesirsa.com\/index.php\/wp-json\/wp\/v2\/media?parent=5259"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}